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math word problem help?

Mathematics
Jazzy asked:


ok……..the attendance at a baseball game was 400 people. student tickets cost $2 and adult tickets cost $3. total ticket sales were $1050. how many tickets of each type were sold?

how would i write an equation for this problem??

Norma

6 Comments

6 Comments

  1. Jay  •  May 8, 2010 @10:11 am

    Nicholas

    Students = s
    Adults = a

    400 = s + a (no of people)
    1050 = 2s + 3a (tickets sold)

  2. RJ  •  May 10, 2010 @8:08 pm

    Lori

    i’m gonna solve using one variable to make this as simple as possible

    let:
    x = number of students
    400-x = number of adults

    2x+3(400-x)=1050

    2x+1200-3x=1050

    -x=-150

    x=150

    students = 150

    adults = 400-x = 400-150 = 250

    so students = 150 adults = 250

    you can also solve this using systems of equations

  3. artie  •  May 11, 2010 @10:27 pm

    Annette

    Ok. Let’s say A=adult entrance and S=student entrance, so:

    A+S = 400

    Also, you know that: 2*S + 3*A = 1050 (total ticket sales)

    so: 2*S = 1050 – 3*A, and then:

    S = (1050 – 3*A) / 2.

    So, going back to the first equation A+S = 400:

    A + (1050 – 3*A)/2 = 400

    A + 1050/2 – 3*A/2 = 400, rearranging and solving:

    1050/2 – 400 = A /2
    1050 – 800 = A

    A = 250, then B = 150

  4. Mariluz  •  May 13, 2010 @4:38 am

    Brenda

    First of all, you need to set your variables:
    let x be the number of student tickets sold and let y be the number of adult tickets sold.
    We have then 2 equations with two variables:

    x + y = 400 (total number of tickets sold)
    2x + 3y = 1050 (total sales)

    you can solve by many methods this system. The solution is:

    x = 150 and y = 250, if you test the answer:
    150 + 250 = 400
    2(150) + 3(250) = 1050.

    Good Luck

  5. Ali  •  May 13, 2010 @8:49 pm

    Cindy

    You should take:

    x for adults
    y for student

    we have 400 people in the game, and these people are adults and students. so: x + y = 400

    And, the ticket cost for one adults is $3 and for one student is $2 and the total ticket sales was $1050. so, we have got another equation: 3x + 2y = 1050.

    Take the equation x + y = 400 => x = 400 – y

    Replace the value of x in the second equation:

    3x + 2y = 1050
    3(400 – y) +2y = 1050
    1200 – 3y + 2y = 1050
    -y = 1050 – 1200
    y = 150

    So, there were 150 adult in the game.

    Finally, take x + y = 400.
    Replace the value of y:
    x + 150 = 400
    x = 400 – 150 = 250.

    So, there were 250 students in the game.

    That’s it.

  6. xl4000  •  May 14, 2010 @4:10 am

    Edna

    Let X represent the number of students
    Let Y represent the number of adults

    X+Y=400
    2X+3Y=1050

    Solve simultaneously

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